Let us play around a little with the reduced single pulse MPEr assuming it is the most

restrictive criterion.

Dimensions and definitions:

quantity

unit

*10^{-3}

*10^{-6}

10^{-9}

Length

**m**

mm

Time

**s**

Angle

**rad**

Solid Angle

**sr**

Power

**W**

Energy

**J**

Standard aperture:

Counting time for pulses:

for a point source

Expression for MPE of the standard:

Remember C5:=N^-0.25, when N = number of pulse during T2.

The duration function is given as

__duration function with:__

a see above

d = beam diameter

T = cycle time of the figure = 1/f

r = radius of the moving dot

in the spectator's area

s = 1 second

We take a safety factor because of the higher intensity close to the center of the beam.

From this you can calculate the Watts in the beam of diameter d in the spectator's plane.

To follow this simplification keep in mind the factor n*t with n= T2/T

and the speed of the dot, given by 2*p*r/T.

As you can see the formula is independant of the cycle time T (hence the

frequency) of the figure. The result will be Watts, the total power of the beam.

Now assume some data:

This value comes to the same order of magnitude as in the example you sent to here.

__Now I try to come to 10 W???__

Bad laser quality leads to C6 = 3 ... 5 possibly:

A very long path through the room (corresponding to seldom hits) leads to a big r

Finally we take a big beam, making long pulses but spreading the power over a

wide range (big dot of light):

or take a beam of diameter of 20 cm

If you can make sure the single hits are only relevant during 0.25 s in 100 s
(?), than

T2 is limited to 0.25 s of course and you get:

fnmper(C62, d3, r2) = 8.9 W